Hamish & Jazz
In trying to determine the possible color results of a breeding it can be important to know not only the sire and dam's colors, but also the colors of their parents and the colors of any puppies they may have already produced

Hamish - Pelyma Whoops I'm White (brown pigmented cream w/ a white blaze and chest/NO other markings) - sire = black brindle & dam = blue - since Hamish is a brown pigmented cream we know that both his parents carry that gene, he could be a black, blue, brindle, blue brindle, fawn or blue fawn hidden by the cream "masking gene." The presence of the 3 blue puppies in this litter show that he must be either black or blue under the cream. Since the entire litter is blue dilute it is probably safe to consider him a blue.

Jazz - Sandsprings Smart Cookie of Shandril (fawn/blue mask) - sire = red fawn & dam = red fawn parti - since Jazz is blue fawn, we know that both her parents carry that gene, she can only pass on the genes for red, blue dilute, and white parti

Note: yellow, red and fawn are "lumped" together genetically

(7 puppies)
4 blue brindle
3 blues

A locus

Hamish = AyAy (pure for red/fawn)
Jazz = AyAy (pure for red/fawn)

C locus

Hamish is a brown pigmented cream with visible white and is dark enough to see the difference, Jazz a red fawn, and none of the puppies is pale - so we will assume the following:

Hamish = CC (pure for complete expression of red/yellow and blue pigments)
Jazz = CC (ditto)

D locus

Hamish is a brown pigmented cream and the presence of the blue and blue fawn puppies tells us that he carries that gene, Jazz is a blue fawn. Since the litter is of a good size and ALL of the puppies are blue dilute, we have:

Hamish = dd (pure for blue)
Jazz = dd (ditto)

E locus

Because Hamish is brown pigmented cream we can't see a mask (he may or may not have one) and we know that Jazz has a mask, as do at least 2 of the brindle puppies.

Hamish = EE or E^m (expresses dark pigment and may carry mask)
Jazz = EE^m - (expresses dark pigment and carries the mask)

K locus

We know that Hamish could have inherited brindle from his sire, and since there are brindles in the litter we know he carries it. Jazz is not brindle, so cannot have that gene.

Hamish = Kk^br - dark, carrying brindle
Jazz = kk - not dark, not brindle

R locus

Since neither the parents nor any of the puppies are described as Roan we will assume the following:

Hamish = rr (displays normal color and does not carry Roan)
Jazz = rr (ditto)

S locus

We already know that Hamish displays a small amount of white (he may still be a genetic solid color) and Jazz does not - but we know she carries it from her dam, but none of the puppies appears to display a significant amount of white. So now we know:

Hamish = SS (solid)
Jazz = Ss^p (solid, carrying parti-color)

T locus

Not enough data to tell.

CREAM - I am not aware of any genetic notation for this gene, but brown pigmented cream is recessive

Hamish - Pelyma Whoops I'm White - brown pigmented cream w/white = AyAy CC dd EE or E^m Kk^brrr SS CREAM
Jazz - Sandsprings Smart Cookie of Shandril - red fawn/white = AyAy CC dd EE^m kk rr Ss^p

Genetic notation is simply a "short-hand" method of conveying information about the genes carried and/or displayed.  Dominant genes are noted as UPPERCASE and are listed first at each locus, when they are present. Recessive genes are noted as lower case and are listed second at each locus, when a dominant is present.  In the case of 2 dominants or 2 recessives at the same locus the one that is dominant over it's locus partner is listed first. Superscript letters provide futher description of the particular gene's actions.  The above examples convey quick information about what colors these parents can be expected to produce:

Hamish = AyAy CC dd EE or E^m Kk^br rr SS

AyAy = red/fawn, but this color is not displayed on the dog because the presence of the "K" gene inhibits it's expression and because the action of the "masking cream" gene hides the expression of the other color genes

CC = full expression of pigment, not "washed out" in shade
dd = pure for the blue dilution of black, this gene is expressed because the "K" gene allow expression of black and this gene .......then acts to alter the shade of color from black to blue but this is not visible because he is a "masking cream" and the .......cream hides the expression of the other color genes
E = allows expression of the black/blue provided by the action of the "K" and "dd" genes
E^m = same as for the "E" gene, but allows the further expression the "mask" pattern - in Hamish the action of this gene is .......not visible (if he carries it) because he is a "masking cream" and the cream hides the expression of the other color .......genes
rr = not Roaned
S = solid color with no white (or, as in this case, minimal white caused by the expression of minus modifiers that prevent the .......laying down of the base color in restricted areas)
CREAM - pure for "masking cream"

Jazz = AyAy CC dd EE^m kk rr Ss^p

AyAy = pure for red/fawn, since Jazz is neither blue nor black she cannot carry the "K" gene as Hamish does
CC = full expression of pigment, not "washed out" in shade
dd = pure for the blue dilution, this gene is expressed because the "a^y" genes allow expression of red and this gene then .......acts to alter the shade of color to blue fawn
E = allows the expression of dark pigment, but since Jazz is pure for fawn at the K locus she has no dark pigment to display
E^m = allows expression of the mask
rr = not Roaned
s^ps^p = parti-colored with more or less equal amounts of white and fawn.  Since all of Allie's puppies that display white are .......described as Irish Marked they must have inherited the gene from Bo, and Allie's "s^p" contribution is inhibited by the .......action of the "sⁱ" gene contributed by Bo

solid blue = AyAy CC dd EE or E^m Kk or k^br or rr SS or Ss^p carrying CREAM
solid blue brindle = AyAy CC dd EE or E^m k^brk rr Ss^p carrying CREAM

All of Hamish and Jazz's puppies will carry "masking cream", since Hamish has no other gene to contribute at that locus. Also, they may carry white spotting from Jazz. All of the brindle puppies will carry non-brindle red/fawn.